Base | Representation |
---|---|
bin | 11001001101000001… |
… | …01110100001001111 |
3 | 1021220222222210102212 |
4 | 30212200232201033 |
5 | 210202414441442 |
6 | 10114400341035 |
7 | 656211506021 |
oct | 144640564117 |
9 | 37828883385 |
10 | 13531015247 |
11 | 58139a6032 |
12 | 275761477b |
13 | 13783c5bc9 |
14 | 9250b6011 |
15 | 542d94a82 |
hex | 32682e84f |
13531015247 has 2 divisors, whose sum is σ = 13531015248. Its totient is φ = 13531015246.
The previous prime is 13531015213. The next prime is 13531015249. The reversal of 13531015247 is 74251013531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13531015247 - 216 = 13530949711 is a prime.
It is a super-2 number, since 2×135310152472 (a number of 21 digits) contains 22 as substring.
Together with 13531015249, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13531015249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765507623 + 6765507624.
It is an arithmetic number, because the mean of its divisors is an integer number (6765507624).
Almost surely, 213531015247 is an apocalyptic number.
13531015247 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531015247 is an equidigital number, since it uses as much as digits as its factorization.
13531015247 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12600, while the sum is 32.
Adding to 13531015247 its reverse (74251013531), we get a palindrome (87782028778).
The spelling of 13531015247 in words is "thirteen billion, five hundred thirty-one million, fifteen thousand, two hundred forty-seven".
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