Base | Representation |
---|---|
bin | 11001001101000001… |
… | …10001000000111111 |
3 | 1021221000000022110112 |
4 | 30212200301000333 |
5 | 210202420303341 |
6 | 10114400500235 |
7 | 656211550565 |
oct | 144640610077 |
9 | 37830008415 |
10 | 13531025471 |
11 | 5813a02787 |
12 | 275761a67b |
13 | 13783ca762 |
14 | 9250b9a35 |
15 | 542d97aeb |
hex | 32683103f |
13531025471 has 2 divisors, whose sum is σ = 13531025472. Its totient is φ = 13531025470.
The previous prime is 13531025411. The next prime is 13531025477. The reversal of 13531025471 is 17452013531.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13531025471 is a prime.
It is a super-3 number, since 3×135310254713 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13531025477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765512735 + 6765512736.
It is an arithmetic number, because the mean of its divisors is an integer number (6765512736).
Almost surely, 213531025471 is an apocalyptic number.
13531025471 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531025471 is an equidigital number, since it uses as much as digits as its factorization.
13531025471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12600, while the sum is 32.
The spelling of 13531025471 in words is "thirteen billion, five hundred thirty-one million, twenty-five thousand, four hundred seventy-one".
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