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13531025477 is a prime number
BaseRepresentation
bin11001001101000001…
…10001000001000101
31021221000000022110202
430212200301001011
5210202420303402
610114400500245
7656211550604
oct144640610105
937830008422
1013531025477
115813a02792
12275761a685
1313783ca768
149250b9a3b
15542d97b02
hex326831045

13531025477 has 2 divisors, whose sum is σ = 13531025478. Its totient is φ = 13531025476.

The previous prime is 13531025471. The next prime is 13531025479. The reversal of 13531025477 is 77452013531.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11705941636 + 1825083841 = 108194^2 + 42721^2 .

It is a cyclic number.

It is not a de Polignac number, because 13531025477 - 222 = 13526831173 is a prime.

Together with 13531025479, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13531025477.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13531025471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765512738 + 6765512739.

It is an arithmetic number, because the mean of its divisors is an integer number (6765512739).

Almost surely, 213531025477 is an apocalyptic number.

It is an amenable number.

13531025477 is a deficient number, since it is larger than the sum of its proper divisors (1).

13531025477 is an equidigital number, since it uses as much as digits as its factorization.

13531025477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 88200, while the sum is 38.

The spelling of 13531025477 in words is "thirteen billion, five hundred thirty-one million, twenty-five thousand, four hundred seventy-seven".