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1353120301397 is a prime number
BaseRepresentation
bin10011101100001100010…
…000010100000101010101
311210100122021120100200102
4103230030100110011111
5134132142244121042
62513340452023445
7166521403534634
oct23541420240525
94710567510612
101353120301397
11481945152927
1219a2b1301b85
139a7a244c847
14496c447951b
15252e76c3b32
hex13b0c414155

1353120301397 has 2 divisors, whose sum is σ = 1353120301398. Its totient is φ = 1353120301396.

The previous prime is 1353120301387. The next prime is 1353120301457. The reversal of 1353120301397 is 7931030213531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1352880701956 + 239599441 = 1163134^2 + 15479^2 .

It is an emirp because it is prime and its reverse (7931030213531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1353120301397 - 240 = 253608673621 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1353120301397.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1353120301307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676560150698 + 676560150699.

It is an arithmetic number, because the mean of its divisors is an integer number (676560150699).

Almost surely, 21353120301397 is an apocalyptic number.

It is an amenable number.

1353120301397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353120301397 is an equidigital number, since it uses as much as digits as its factorization.

1353120301397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51030, while the sum is 38.

The spelling of 1353120301397 in words is "one trillion, three hundred fifty-three billion, one hundred twenty million, three hundred one thousand, three hundred ninety-seven".