Base | Representation |
---|---|
bin | 11001001101000010… |
… | …11110011001010110 |
3 | 1021221000100202102221 |
4 | 30212201132121112 |
5 | 210202442230400 |
6 | 10114404452554 |
7 | 656213253526 |
oct | 144641363126 |
9 | 37830322387 |
10 | 13531211350 |
11 | 581401a3a8 |
12 | 27576aa15a |
13 | 1378464247 |
14 | 925127686 |
15 | 542dd2c1a |
hex | 32685e656 |
13531211350 has 24 divisors (see below), whose sum is σ = 25184403720. Its totient is φ = 5408968320.
The previous prime is 13531211347. The next prime is 13531211377. The reversal of 13531211350 is 5311213531.
13531211350 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 9480 + ... + 164779.
It is an arithmetic number, because the mean of its divisors is an integer number (1049350155).
Almost surely, 213531211350 is an apocalyptic number.
13531211350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13531211350 is a deficient number, since it is larger than the sum of its proper divisors (11653192370).
13531211350 is a wasteful number, since it uses less digits than its factorization.
13531211350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 175824 (or 175819 counting only the distinct ones).
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 13531211350 its reverse (5311213531), we get a palindrome (18842424881).
The spelling of 13531211350 in words is "thirteen billion, five hundred thirty-one million, two hundred eleven thousand, three hundred fifty".
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