Base | Representation |
---|---|
bin | 10011101100011010001… |
… | …000001001000101111010 |
3 | 11210101020111111201100221 |
4 | 103230122020021011322 |
5 | 134133131334242000 |
6 | 2513415524250254 |
7 | 166530231015601 |
oct | 23543210110572 |
9 | 4711214451327 |
10 | 1353353040250 |
11 | 481a54566a92 |
12 | 19a35724098a |
13 | 9a80b72a643 |
14 | 49707340a38 |
15 | 2530cd4861a |
hex | 13b1a20917a |
1353353040250 has 64 divisors (see below), whose sum is σ = 2540479324032. Its totient is φ = 539847168000.
The previous prime is 1353353040241. The next prime is 1353353040253. The reversal of 1353353040250 is 520403533531.
It is not an unprimeable number, because it can be changed into a prime (1353353040253) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 142859514 + ... + 142868986.
It is an arithmetic number, because the mean of its divisors is an integer number (39694989438).
Almost surely, 21353353040250 is an apocalyptic number.
1353353040250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1353353040250 is a deficient number, since it is larger than the sum of its proper divisors (1187126283782).
1353353040250 is an equidigital number, since it uses as much as digits as its factorization.
1353353040250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11008 (or 10998 counting only the distinct ones).
The product of its (nonzero) digits is 81000, while the sum is 34.
Adding to 1353353040250 its reverse (520403533531), we get a palindrome (1873756573781).
The spelling of 1353353040250 in words is "one trillion, three hundred fifty-three billion, three hundred fifty-three million, forty thousand, two hundred fifty".
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