13540444061 has 2 divisors, whose sum is σ = 13540444062. Its totient is φ = 13540444060.

The previous prime is 13540443977. The next prime is 13540444063. The reversal of 13540444061 is 16044404531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12546240100 + 994203961 = 112010^2 + 31531^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13540444061 is a prime.

Together with 13540444063, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13540444063) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6770222030 + 6770222031.

It is an arithmetic number, because the mean of its divisors is an integer number (6770222031).

Almost surely, 2^13540444061 is an apocalyptic number.

It is an amenable number.

13540444061 is a deficient number, since it is larger than the sum of its proper divisors (1).

13540444061 is an equidigital number, since it uses as much as digits as its factorization.

13540444061 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 32.

Adding to 13540444061 its reverse (16044404531), we get a palindrome (29584848592).

The spelling of 13540444061 in words is "thirteen billion, five hundred forty million, four hundred forty-four thousand, sixty-one".