Base | Representation |
---|---|
bin | 11110110011000110111001… |
… | …110000100100100000010110 |
3 | 122202121020011022122001101010 |
4 | 132303012321300210200112 |
5 | 120223232232013200400 |
6 | 1200030251240113050 |
7 | 40350123002035152 |
oct | 3663067160444026 |
9 | 582536138561333 |
10 | 135453500131350 |
11 | 3a183563616675 |
12 | 13237967165786 |
13 | 5a77296c0b82b |
14 | 2563dad22c062 |
15 | 109d6ca48e450 |
hex | 7b31b9c24816 |
135453500131350 has 48 divisors (see below), whose sum is σ = 335975129519040. Its totient is φ = 36115508724000.
The previous prime is 135453500131343. The next prime is 135453500131357. The reversal of 135453500131350 is 53131005354531.
135453500131350 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (135453500131343) and next prime (135453500131357).
It is a junction number, because it is equal to n+sod(n) for n = 135453500131299 and 135453500131308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135453500131357) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 66805876 + ... + 68803575.
It is an arithmetic number, because the mean of its divisors is an integer number (6999481864980).
Almost surely, 2135453500131350 is an apocalyptic number.
135453500131350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
135453500131350 is an abundant number, since it is smaller than the sum of its proper divisors (200521629387690).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135453500131350 is a wasteful number, since it uses less digits than its factorization.
135453500131350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 135616125 (or 135616120 counting only the distinct ones).
The product of its (nonzero) digits is 202500, while the sum is 39.
Adding to 135453500131350 its reverse (53131005354531), we get a palindrome (188584505485881).
The spelling of 135453500131350 in words is "one hundred thirty-five trillion, four hundred fifty-three billion, five hundred million, one hundred thirty-one thousand, three hundred fifty".
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