Base | Representation |
---|---|
bin | 11110110100000111111100… |
… | …001101111110010010100010 |
3 | 122202211220102012112020120020 |
4 | 132310013330031332102202 |
5 | 120230403242130042010 |
6 | 1200122321015254310 |
7 | 40355144366240403 |
oct | 3664077415762242 |
9 | 582756365466506 |
10 | 135523334612130 |
11 | 3a20013a3366a3 |
12 | 132493b667a396 |
13 | 5a80a45c824ca |
14 | 2567515c799aa |
15 | 10a04162a7470 |
hex | 7b41fc37e4a2 |
135523334612130 has 32 divisors (see below), whose sum is σ = 326238649627968. Its totient is φ = 36030372945600.
The previous prime is 135523334612089. The next prime is 135523334612189. The reversal of 135523334612130 is 31216433325531.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6823924341 + ... + 6823944200.
It is an arithmetic number, because the mean of its divisors is an integer number (10194957800874).
Almost surely, 2135523334612130 is an apocalyptic number.
135523334612130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
135523334612130 is an abundant number, since it is smaller than the sum of its proper divisors (190715315015838).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135523334612130 is a wasteful number, since it uses less digits than its factorization.
135523334612130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13647868882.
The product of its (nonzero) digits is 583200, while the sum is 42.
Adding to 135523334612130 its reverse (31216433325531), we get a palindrome (166739767937661).
The spelling of 135523334612130 in words is "one hundred thirty-five trillion, five hundred twenty-three billion, three hundred thirty-four million, six hundred twelve thousand, one hundred thirty".
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