Base | Representation |
---|---|
bin | 1100010101000000101011… |
… | …1110111000101010010110 |
3 | 1202222212002022001021010100 |
4 | 3011100022332320222112 |
5 | 3234041321331341400 |
6 | 44455043310234530 |
7 | 2566216016540226 |
oct | 305201276705226 |
9 | 52885068037110 |
10 | 13555101043350 |
11 | 4356760181649 |
12 | 162b09bab5a46 |
13 | 774318622149 |
14 | 34c0db220086 |
15 | 1878ec8c5100 |
hex | c540afb8a96 |
13555101043350 has 36 divisors (see below), whose sum is σ = 36418038137676. Its totient is φ = 3614693611440.
The previous prime is 13555101043339. The next prime is 13555101043381. The reversal of 13555101043350 is 5334010155531.
13555101043350 is a `hidden beast` number, since 1 + 3 + 5 + 5 + 510 + 104 + 3 + 35 + 0 = 666.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 15061222932 + ... + 15061223831.
It is an arithmetic number, because the mean of its divisors is an integer number (1011612170491).
Almost surely, 213555101043350 is an apocalyptic number.
13555101043350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13555101043350 is an abundant number, since it is smaller than the sum of its proper divisors (22862937094326).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13555101043350 is a wasteful number, since it uses less digits than its factorization.
13555101043350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 30122446781 (or 30122446773 counting only the distinct ones).
The product of its (nonzero) digits is 67500, while the sum is 36.
Adding to 13555101043350 its reverse (5334010155531), we get a palindrome (18889111198881).
The spelling of 13555101043350 in words is "thirteen trillion, five hundred fifty-five billion, one hundred one million, forty-three thousand, three hundred fifty".
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