Base | Representation |
---|---|
bin | 1100010101011000001010… |
… | …1110100100111000100010 |
3 | 1210000110100122001111122120 |
4 | 3011112002232210320202 |
5 | 3234142224140020000 |
6 | 44502005022045110 |
7 | 2566531154361231 |
oct | 305260256447042 |
9 | 53013318044576 |
10 | 13561405001250 |
11 | 43593a563a507 |
12 | 163035b119796 |
13 | 774ab1673352 |
14 | 34c538552b18 |
15 | 187b6b04e6a0 |
hex | c5582ba4e22 |
13561405001250 has 80 divisors (see below), whose sum is σ = 34356947132640. Its totient is φ = 3566835216000.
The previous prime is 13561405001219. The next prime is 13561405001267. The reversal of 13561405001250 is 5210050416531.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 24495940 + ... + 25043439.
It is an arithmetic number, because the mean of its divisors is an integer number (429461839158).
Almost surely, 213561405001250 is an apocalyptic number.
13561405001250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13561405001250 is an abundant number, since it is smaller than the sum of its proper divisors (20795542131390).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13561405001250 is an equidigital number, since it uses as much as digits as its factorization.
13561405001250 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49539477 (or 49539462 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 13561405001250 its reverse (5210050416531), we get a palindrome (18771455417781).
The spelling of 13561405001250 in words is "thirteen trillion, five hundred sixty-one billion, four hundred five million, one thousand, two hundred fifty".
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