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135614110123013 is a prime number
BaseRepresentation
bin11110110101011100011110…
…110111000100010000000101
3122210011120201111122222121212
4132311130132313010100011
5120233400144142414023
61200232132341421205
740364540033323544
oct3665343667042005
9583146644588555
10135614110123013
113a235691791575
1213262b0b10a805
135a89481661b62
14256ba87b6a15b
1510a297a76ee78
hex7b571edc4405

135614110123013 has 2 divisors, whose sum is σ = 135614110123014. Its totient is φ = 135614110123012.

The previous prime is 135614110123001. The next prime is 135614110123043. The reversal of 135614110123013 is 310321011416531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127973629126849 + 7640480996164 = 11312543^2 + 2764142^2 .

It is a cyclic number.

It is not a de Polignac number, because 135614110123013 - 210 = 135614110121989 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135614110123043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67807055061506 + 67807055061507.

It is an arithmetic number, because the mean of its divisors is an integer number (67807055061507).

Almost surely, 2135614110123013 is an apocalyptic number.

It is an amenable number.

135614110123013 is a deficient number, since it is larger than the sum of its proper divisors (1).

135614110123013 is an equidigital number, since it uses as much as digits as its factorization.

135614110123013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 32.

Adding to 135614110123013 its reverse (310321011416531), we get a palindrome (445935121539544).

The spelling of 135614110123013 in words is "one hundred thirty-five trillion, six hundred fourteen billion, one hundred ten million, one hundred twenty-three thousand, thirteen".