Base | Representation |
---|---|
bin | 11110110101011100011110… |
… | …110111000100010000000101 |
3 | 122210011120201111122222121212 |
4 | 132311130132313010100011 |
5 | 120233400144142414023 |
6 | 1200232132341421205 |
7 | 40364540033323544 |
oct | 3665343667042005 |
9 | 583146644588555 |
10 | 135614110123013 |
11 | 3a235691791575 |
12 | 13262b0b10a805 |
13 | 5a89481661b62 |
14 | 256ba87b6a15b |
15 | 10a297a76ee78 |
hex | 7b571edc4405 |
135614110123013 has 2 divisors, whose sum is σ = 135614110123014. Its totient is φ = 135614110123012.
The previous prime is 135614110123001. The next prime is 135614110123043. The reversal of 135614110123013 is 310321011416531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127973629126849 + 7640480996164 = 11312543^2 + 2764142^2 .
It is a cyclic number.
It is not a de Polignac number, because 135614110123013 - 210 = 135614110121989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135614110123043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67807055061506 + 67807055061507.
It is an arithmetic number, because the mean of its divisors is an integer number (67807055061507).
Almost surely, 2135614110123013 is an apocalyptic number.
It is an amenable number.
135614110123013 is a deficient number, since it is larger than the sum of its proper divisors (1).
135614110123013 is an equidigital number, since it uses as much as digits as its factorization.
135614110123013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 32.
Adding to 135614110123013 its reverse (310321011416531), we get a palindrome (445935121539544).
The spelling of 135614110123013 in words is "one hundred thirty-five trillion, six hundred fourteen billion, one hundred ten million, one hundred twenty-three thousand, thirteen".
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