Base | Representation |
---|---|
bin | 111111001010101111… |
… | …1001101000101110111 |
3 | 110222010211010010212122 |
4 | 1332111133031011313 |
5 | 4210303401041242 |
6 | 142152340310155 |
7 | 12541403506136 |
oct | 1762537150567 |
9 | 428124103778 |
10 | 135651971447 |
11 | 52591001a13 |
12 | 223596a235b |
13 | ca3ab27835 |
14 | 67cbda191d |
15 | 37de151ad2 |
hex | 1f957cd177 |
135651971447 has 2 divisors, whose sum is σ = 135651971448. Its totient is φ = 135651971446.
The previous prime is 135651971443. The next prime is 135651971449. The reversal of 135651971447 is 744179156531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135651971447 - 22 = 135651971443 is a prime.
Together with 135651971449, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135651971443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67825985723 + 67825985724.
It is an arithmetic number, because the mean of its divisors is an integer number (67825985724).
Almost surely, 2135651971447 is an apocalyptic number.
135651971447 is a deficient number, since it is larger than the sum of its proper divisors (1).
135651971447 is an equidigital number, since it uses as much as digits as its factorization.
135651971447 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3175200, while the sum is 53.
The spelling of 135651971447 in words is "one hundred thirty-five billion, six hundred fifty-one million, nine hundred seventy-one thousand, four hundred forty-seven".
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