Base | Representation |
---|---|
bin | 10011110011011110111… |
… | …100111110111010110000 |
3 | 11211002211221220002212211 |
4 | 103303132330332322300 |
5 | 134244211222200330 |
6 | 2521113433501504 |
7 | 200216420530456 |
oct | 23633674767260 |
9 | 4732757802784 |
10 | 1360950193840 |
11 | 4851a29a4a16 |
12 | 19b917571894 |
13 | 9b44c6736b3 |
14 | 49c283029d6 |
15 | 25604cbbd2a |
hex | 13cdef3eeb0 |
1360950193840 has 80 divisors (see below), whose sum is σ = 3178450360800. Its totient is φ = 541931581440.
The previous prime is 1360950193831. The next prime is 1360950193843. The reversal of 1360950193840 is 483910590631.
It is a tau number, because it is divible by the number of its divisors (80).
It is a super-2 number, since 2×13609501938402 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1360950193843) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63594022 + ... + 63615418.
It is an arithmetic number, because the mean of its divisors is an integer number (39730629510).
Almost surely, 21360950193840 is an apocalyptic number.
1360950193840 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1360950193840 is an abundant number, since it is smaller than the sum of its proper divisors (1817500166960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1360950193840 is a wasteful number, since it uses less digits than its factorization.
1360950193840 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24950 (or 24944 counting only the distinct ones).
The product of its (nonzero) digits is 699840, while the sum is 49.
The spelling of 1360950193840 in words is "one trillion, three hundred sixty billion, nine hundred fifty million, one hundred ninety-three thousand, eight hundred forty".
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