Base | Representation |
---|---|
bin | 11110111100110101000100… |
… | …101001000101100110011110 |
3 | 122211222002111212120101210100 |
4 | 132330311010221011212132 |
5 | 120320203413313234122 |
6 | 1201301213222121530 |
7 | 40446312623255322 |
oct | 3674650451054636 |
9 | 584862455511710 |
10 | 136121550133662 |
11 | 3a4109094070a5 |
12 | 133253278802a6 |
13 | 5ac528ccc57a2 |
14 | 2588465127982 |
15 | 10b0c79635aac |
hex | 7bcd44a4599e |
136121550133662 has 24 divisors (see below), whose sum is σ = 310452658200360. Its totient is φ = 42985752673680.
The previous prime is 136121550133627. The next prime is 136121550133697. The reversal of 136121550133662 is 266331055121631.
136121550133662 is a `hidden beast` number, since 1 + 3 + 6 + 1 + 2 + 1 + 550 + 1 + 3 + 36 + 62 = 666.
It is an interprime number because it is at equal distance from previous prime (136121550133627) and next prime (136121550133697).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 199008113889 + ... + 199008114572.
It is an arithmetic number, because the mean of its divisors is an integer number (12935527425015).
Almost surely, 2136121550133662 is an apocalyptic number.
136121550133662 is an abundant number, since it is smaller than the sum of its proper divisors (174331108066698).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
136121550133662 is a wasteful number, since it uses less digits than its factorization.
136121550133662 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 398016228488 (or 398016228485 counting only the distinct ones).
The product of its (nonzero) digits is 583200, while the sum is 45.
The spelling of 136121550133662 in words is "one hundred thirty-six trillion, one hundred twenty-one billion, five hundred fifty million, one hundred thirty-three thousand, six hundred sixty-two".
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