1361250330040 has 32 divisors (see below), whose sum is σ = 3093138135360. Its totient is φ = 539109040000.

The previous prime is 1361250330019. The next prime is 1361250330053. The reversal of 1361250330040 is 400330521631.

It is a super-2 number, since 2×1361250330040² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1361250329990 and 1361250330008.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 168467536 + ... + 168475615.

It is an arithmetic number, because the mean of its divisors is an integer number (96660566730).

Almost surely, 2^{1361250330040} is an apocalyptic number.

1361250330040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1361250330040 is an abundant number, since it is smaller than the sum of its proper divisors (1731887805320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1361250330040 is a wasteful number, since it uses less digits than its factorization.

1361250330040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 336943263 (or 336943259 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 28.

Adding to 1361250330040 its reverse (400330521631), we get a palindrome (1761580851671).

The spelling of 1361250330040 in words is "one trillion, three hundred sixty-one billion, two hundred fifty million, three hundred thirty thousand, forty".