Base | Representation |
---|---|
bin | 10011110011110000111… |
… | …100101111111110101100 |
3 | 11211010122000000200012021 |
4 | 103303300330233332230 |
5 | 134300321020410130 |
6 | 2521203421115524 |
7 | 200230045062202 |
oct | 23636074577654 |
9 | 4733560020167 |
10 | 1361252122540 |
11 | 485338376472 |
12 | 19b9a06b8ba4 |
13 | 9b49a09832b |
14 | 49c56459072 |
15 | 2562155c37a |
hex | 13cf0f2ffac |
1361252122540 has 24 divisors (see below), whose sum is σ = 2859157399392. Its totient is φ = 544400288640.
The previous prime is 1361252122453. The next prime is 1361252122591. The reversal of 1361252122540 is 452212521631.
It is a happy number.
It is a super-2 number, since 2×13612521225402 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1361252122496 and 1361252122505.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6173976 + ... + 6390655.
It is an arithmetic number, because the mean of its divisors is an integer number (119131558308).
Almost surely, 21361252122540 is an apocalyptic number.
1361252122540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1361252122540 is an abundant number, since it is smaller than the sum of its proper divisors (1497905276852).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1361252122540 is a wasteful number, since it uses less digits than its factorization.
1361252122540 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12570057 (or 12570055 counting only the distinct ones).
The product of its (nonzero) digits is 28800, while the sum is 34.
The spelling of 1361252122540 in words is "one trillion, three hundred sixty-one billion, two hundred fifty-two million, one hundred twenty-two thousand, five hundred forty".
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