Base | Representation |
---|---|
bin | 10011110011110010000… |
… | …101101000010000110111 |
3 | 11211010200022222022012102 |
4 | 103303302011220100313 |
5 | 134300340413234242 |
6 | 2521205342412315 |
7 | 200230366342505 |
oct | 23636205502067 |
9 | 4733608868172 |
10 | 1361271227447 |
11 | 48534813524a |
12 | 19b9a6b9109b |
13 | 9b4a1027201 |
14 | 49c58bcd675 |
15 | 25623082e32 |
hex | 13cf2168437 |
1361271227447 has 2 divisors, whose sum is σ = 1361271227448. Its totient is φ = 1361271227446.
The previous prime is 1361271227431. The next prime is 1361271227461. The reversal of 1361271227447 is 7447221721631.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1361271227447 - 24 = 1361271227431 is a prime.
It is a super-2 number, since 2×13612712274472 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1361271227047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 680635613723 + 680635613724.
It is an arithmetic number, because the mean of its divisors is an integer number (680635613724).
Almost surely, 21361271227447 is an apocalyptic number.
1361271227447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1361271227447 is an equidigital number, since it uses as much as digits as its factorization.
1361271227447 is an evil number, because the sum of its binary digits is even.
The product of its digits is 790272, while the sum is 47.
The spelling of 1361271227447 in words is "one trillion, three hundred sixty-one billion, two hundred seventy-one million, two hundred twenty-seven thousand, four hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •