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1363879391111 is a prime number
BaseRepresentation
bin10011110110001101100…
…010111110111110000111
311211101102002200202010122
4103312031202332332013
5134321211111003421
62522320232412155
7200352126354266
oct23661542767607
94741362622118
101363879391111
114864663a6206
121a03b454705b
139b7c8497c13
144a0253585dd
15257270272ab
hex13d8d8bef87

1363879391111 has 2 divisors, whose sum is σ = 1363879391112. Its totient is φ = 1363879391110.

The previous prime is 1363879391107. The next prime is 1363879391113. The reversal of 1363879391111 is 1111939783631.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1363879391111 - 22 = 1363879391107 is a prime.

Together with 1363879391113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1363879391113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 681939695555 + 681939695556.

It is an arithmetic number, because the mean of its divisors is an integer number (681939695556).

Almost surely, 21363879391111 is an apocalyptic number.

1363879391111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1363879391111 is an equidigital number, since it uses as much as digits as its factorization.

1363879391111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 734832, while the sum is 53.

The spelling of 1363879391111 in words is "one trillion, three hundred sixty-three billion, eight hundred seventy-nine million, three hundred ninety-one thousand, one hundred eleven".