Base | Representation |
---|---|
bin | 11001011010010001… |
… | …11011001100001111 |
3 | 1022012202020101110221 |
4 | 30231020323030033 |
5 | 210414401404312 |
6 | 10133412012211 |
7 | 662031632044 |
oct | 145510731417 |
9 | 38182211427 |
10 | 13642216207 |
11 | 5870747a54 |
12 | 2788901067 |
13 | 139545baa9 |
14 | 935b811cb |
15 | 54ca0d207 |
hex | 32d23b30f |
13642216207 has 2 divisors, whose sum is σ = 13642216208. Its totient is φ = 13642216206.
The previous prime is 13642216187. The next prime is 13642216241. The reversal of 13642216207 is 70261224631.
It is an a-pointer prime, because the next prime (13642216241) can be obtained adding 13642216207 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13642216207 - 231 = 11494732559 is a prime.
It is a super-2 number, since 2×136422162072 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13642214207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6821108103 + 6821108104.
It is an arithmetic number, because the mean of its divisors is an integer number (6821108104).
Almost surely, 213642216207 is an apocalyptic number.
13642216207 is a deficient number, since it is larger than the sum of its proper divisors (1).
13642216207 is an equidigital number, since it uses as much as digits as its factorization.
13642216207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 34.
The spelling of 13642216207 in words is "thirteen billion, six hundred forty-two million, two hundred sixteen thousand, two hundred seven".
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