Base | Representation |
---|---|
bin | 111111110011101101… |
… | …0110011001110101010 |
3 | 111002200121121220022102 |
4 | 1333213122303032222 |
5 | 4221112244024100 |
6 | 142541002253402 |
7 | 12620434305635 |
oct | 1774732631652 |
9 | 432617556272 |
10 | 137026548650 |
11 | 53126a07132 |
12 | 22681ab7262 |
13 | cbc9844824 |
14 | 68bc776c1c |
15 | 386eb73cd5 |
hex | 1fe76b33aa |
137026548650 has 24 divisors (see below), whose sum is σ = 257251347360. Its totient is φ = 54298368560.
The previous prime is 137026548649. The next prime is 137026548653. The reversal of 137026548650 is 56845620731.
It is a hoax number, since the sum of its digits (47) coincides with the sum of the digits of its distinct prime factors.
It is a junction number, because it is equal to n+sod(n) for n = 137026548595 and 137026548604.
It is not an unprimeable number, because it can be changed into a prime (137026548653) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 12800870 + ... + 12811569.
It is an arithmetic number, because the mean of its divisors is an integer number (10718806140).
Almost surely, 2137026548650 is an apocalyptic number.
137026548650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
137026548650 is a deficient number, since it is larger than the sum of its proper divisors (120224798710).
137026548650 is a wasteful number, since it uses less digits than its factorization.
137026548650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25612558 (or 25612553 counting only the distinct ones).
The product of its (nonzero) digits is 1209600, while the sum is 47.
The spelling of 137026548650 in words is "one hundred thirty-seven billion, twenty-six million, five hundred forty-eight thousand, six hundred fifty".
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