Base | Representation |
---|---|
bin | 1100011111111111110011… |
… | …1100010101101011000101 |
3 | 1210122220021010022201200001 |
4 | 3013333330330111223011 |
5 | 3300134343034240444 |
6 | 45121500152121301 |
7 | 2615650160634343 |
oct | 307777474255305 |
9 | 53586233281601 |
10 | 13743844055749 |
11 | 4419805739405 |
12 | 165b795696231 |
13 | 7890676c88c2 |
14 | 3572c4256993 |
15 | 18c7979458d4 |
hex | c7ffcf15ac5 |
13743844055749 has 2 divisors, whose sum is σ = 13743844055750. Its totient is φ = 13743844055748.
The previous prime is 13743844055743. The next prime is 13743844055771. The reversal of 13743844055749 is 94755044834731.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7266528922500 + 6477315133249 = 2695650^2 + 2545057^2 .
It is a cyclic number.
It is not a de Polignac number, because 13743844055749 - 23 = 13743844055741 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13743844055741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6871922027874 + 6871922027875.
It is an arithmetic number, because the mean of its divisors is an integer number (6871922027875).
Almost surely, 213743844055749 is an apocalyptic number.
It is an amenable number.
13743844055749 is a deficient number, since it is larger than the sum of its proper divisors (1).
13743844055749 is an equidigital number, since it uses as much as digits as its factorization.
13743844055749 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 203212800, while the sum is 64.
The spelling of 13743844055749 in words is "thirteen trillion, seven hundred forty-three billion, eight hundred forty-four million, fifty-five thousand, seven hundred forty-nine".
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