1381131838181 has 2 divisors, whose sum is σ = 1381131838182. Its totient is φ = 1381131838180.

The previous prime is 1381131838127. The next prime is 1381131838183. The reversal of 1381131838181 is 1818381311831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 754525025956 + 626606812225 = 868634^2 + 791585^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1381131838181 is a prime.

It is a super-2 number, since 2×1381131838181² (a number of 25 digits) contains 22 as substring.

Together with 1381131838183, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1381131838183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690565919090 + 690565919091.

It is an arithmetic number, because the mean of its divisors is an integer number (690565919091).

Almost surely, 2^{1381131838181} is an apocalyptic number.

It is an amenable number.

1381131838181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1381131838181 is an equidigital number, since it uses as much as digits as its factorization.

1381131838181 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 110592, while the sum is 47.

The spelling of 1381131838181 in words is "one trillion, three hundred eighty-one billion, one hundred thirty-one million, eight hundred thirty-eight thousand, one hundred eighty-one".