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1381239701 is a prime number
BaseRepresentation
bin101001001010100…
…0000101110010101
310120021001020122222
41102111000232111
510312044132301
6345020432125
746141225622
oct12225005625
93507036588
101381239701
11649745916
123266a8645
131902106ca
14d162b349
15813db31b
hex52540b95

1381239701 has 2 divisors, whose sum is σ = 1381239702. Its totient is φ = 1381239700.

The previous prime is 1381239667. The next prime is 1381239703. The reversal of 1381239701 is 1079321831.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1282714225 + 98525476 = 35815^2 + 9926^2 .

It is a cyclic number.

It is not a de Polignac number, because 1381239701 - 214 = 1381223317 is a prime.

It is a super-2 number, since 2×13812397012 = 3815646223237138802, which contains 22 as substring.

Together with 1381239703, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1381239703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690619850 + 690619851.

It is an arithmetic number, because the mean of its divisors is an integer number (690619851).

Almost surely, 21381239701 is an apocalyptic number.

It is an amenable number.

1381239701 is a deficient number, since it is larger than the sum of its proper divisors (1).

1381239701 is an equidigital number, since it uses as much as digits as its factorization.

1381239701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9072, while the sum is 35.

The square root of 1381239701 is about 37165.0333108959. The cubic root of 1381239701 is about 1113.6695643743.

The spelling of 1381239701 in words is "one billion, three hundred eighty-one million, two hundred thirty-nine thousand, seven hundred one".