Base | Representation |
---|---|
bin | 1100100101101111010101… |
… | …0101010011101000011110 |
3 | 1211000022220200002000201011 |
4 | 3021123311111103220132 |
5 | 3303243420130143240 |
6 | 45235053525005434 |
7 | 2626042032661666 |
oct | 311336525235036 |
9 | 54008820060634 |
10 | 13842500631070 |
11 | 4457631807681 |
12 | 167692955387a |
13 | 79545aaa7aa7 |
14 | 35bda2ad11a6 |
15 | 19011dc636ea |
hex | c96f5553a1e |
13842500631070 has 16 divisors (see below), whose sum is σ = 25386623799840. Its totient is φ = 5432528549344.
The previous prime is 13842500630951. The next prime is 13842500631083. The reversal of 13842500631070 is 7013600524831.
It is a super-2 number, since 2×138425006310702 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13058962330 + ... + 13058963389.
It is an arithmetic number, because the mean of its divisors is an integer number (1586663987490).
Almost surely, 213842500631070 is an apocalyptic number.
13842500631070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13842500631070 is a deficient number, since it is larger than the sum of its proper divisors (11544123168770).
13842500631070 is a wasteful number, since it uses less digits than its factorization.
13842500631070 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26117925779.
The product of its (nonzero) digits is 120960, while the sum is 40.
The spelling of 13842500631070 in words is "thirteen trillion, eight hundred forty-two billion, five hundred million, six hundred thirty-one thousand, seventy".
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