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13843362103 is a prime number
BaseRepresentation
bin11001110010010000…
…01111000100110111
31022201202201122202221
430321020033010313
5211322400041403
610205355143211
71000023431164
oct147110170467
938652648687
1013843362103
11596424292a
122824144b07
1313c802782c
1495478106b
155604e1dbd
hex33920f137

13843362103 has 2 divisors, whose sum is σ = 13843362104. Its totient is φ = 13843362102.

The previous prime is 13843362097. The next prime is 13843362109. The reversal of 13843362103 is 30126334831.

13843362103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (13843362097) and next prime (13843362109).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13843362103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13843362109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6921681051 + 6921681052.

It is an arithmetic number, because the mean of its divisors is an integer number (6921681052).

Almost surely, 213843362103 is an apocalyptic number.

13843362103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13843362103 is an equidigital number, since it uses as much as digits as its factorization.

13843362103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 34.

Adding to 13843362103 its reverse (30126334831), we get a palindrome (43969696934).

The spelling of 13843362103 in words is "thirteen billion, eight hundred forty-three million, three hundred sixty-two thousand, one hundred three".