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138445553 is a prime number
BaseRepresentation
bin10000100000010…
…00001011110001
3100122111202121002
420100020023301
5240420224203
621423211345
73300524231
oct1020101361
9318452532
10138445553
1171170214
123a446b55
13228b495c
141455bcc1
15c24ad88
hex84082f1

138445553 has 2 divisors, whose sum is σ = 138445554. Its totient is φ = 138445552.

The previous prime is 138445543. The next prime is 138445591. The reversal of 138445553 is 355544831.

It is a happy number.

It is an a-pointer prime, because the next prime (138445591) can be obtained adding 138445553 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107163904 + 31281649 = 10352^2 + 5593^2 .

It is an emirp because it is prime and its reverse (355544831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 138445553 - 24 = 138445537 is a prime.

It is a super-2 number, since 2×1384455532 = 38334342290951618, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (138445513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69222776 + 69222777.

It is an arithmetic number, because the mean of its divisors is an integer number (69222777).

Almost surely, 2138445553 is an apocalyptic number.

It is an amenable number.

138445553 is a deficient number, since it is larger than the sum of its proper divisors (1).

138445553 is an equidigital number, since it uses as much as digits as its factorization.

138445553 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144000, while the sum is 38.

The square root of 138445553 is about 11766.2888371823. The cubic root of 138445553 is about 517.3204779221.

The spelling of 138445553 in words is "one hundred thirty-eight million, four hundred forty-five thousand, five hundred fifty-three".