Base | Representation |
---|---|
bin | 11001110111101011… |
… | …00100101010011111 |
3 | 1022211221020012211022 |
4 | 30323311210222133 |
5 | 211421013121224 |
6 | 10214101114355 |
7 | 1001114602322 |
oct | 147365445237 |
9 | 38757205738 |
10 | 13888801439 |
11 | 59879590a7 |
12 | 28373b89bb |
13 | 1404577106 |
14 | 95a80c7b9 |
15 | 5644ba65e |
hex | 33bd64a9f |
13888801439 has 2 divisors, whose sum is σ = 13888801440. Its totient is φ = 13888801438.
The previous prime is 13888801417. The next prime is 13888801441. The reversal of 13888801439 is 93410888831.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13888801439 is a prime.
Together with 13888801441, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13888800439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6944400719 + 6944400720.
It is an arithmetic number, because the mean of its divisors is an integer number (6944400720).
Almost surely, 213888801439 is an apocalyptic number.
13888801439 is a deficient number, since it is larger than the sum of its proper divisors (1).
13888801439 is an equidigital number, since it uses as much as digits as its factorization.
13888801439 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1327104, while the sum is 53.
The spelling of 13888801439 in words is "thirteen billion, eight hundred eighty-eight million, eight hundred one thousand, four hundred thirty-nine".
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