Base | Representation |
---|---|
bin | 11001111100101001… |
… | …10011000110111101 |
3 | 1022221211202211102112 |
4 | 30332110303012331 |
5 | 212012204312001 |
6 | 10222151503405 |
7 | 1002132435422 |
oct | 147624630675 |
9 | 38854684375 |
10 | 13930541501 |
11 | 59a9478018 |
12 | 2849387b65 |
13 | 14100cc986 |
14 | 962195d49 |
15 | 567eb2cbb |
hex | 33e5331bd |
13930541501 has 2 divisors, whose sum is σ = 13930541502. Its totient is φ = 13930541500.
The previous prime is 13930541473. The next prime is 13930541503. The reversal of 13930541501 is 10514503931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12966376900 + 964164601 = 113870^2 + 31051^2 .
It is an emirp because it is prime and its reverse (10514503931) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13930541501 - 26 = 13930541437 is a prime.
It is a super-2 number, since 2×139305415012 (a number of 21 digits) contains 22 as substring.
Together with 13930541503, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13930541503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6965270750 + 6965270751.
It is an arithmetic number, because the mean of its divisors is an integer number (6965270751).
Almost surely, 213930541501 is an apocalyptic number.
It is an amenable number.
13930541501 is a deficient number, since it is larger than the sum of its proper divisors (1).
13930541501 is an equidigital number, since it uses as much as digits as its factorization.
13930541501 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8100, while the sum is 32.
The spelling of 13930541501 in words is "thirteen billion, nine hundred thirty million, five hundred forty-one thousand, five hundred one".
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