Base | Representation |
---|---|
bin | 1100101100000010001010… |
… | …1010101101100100000000 |
3 | 1211101200000202201102021200 |
4 | 3023000202222231210000 |
5 | 3312031400130240144 |
6 | 45400500004221200 |
7 | 2636620515231213 |
oct | 313004252554400 |
9 | 54350022642250 |
10 | 13950635399424 |
11 | 4499481a99629 |
12 | 169388769a800 |
13 | 7a2701a25619 |
14 | 36330029b77a |
15 | 192d4c219c69 |
hex | cb022aad900 |
13950635399424 has 54 divisors (see below), whose sum is σ = 40223121082326. Its totient is φ = 4650211799040.
The previous prime is 13950635399377. The next prime is 13950635399453. The reversal of 13950635399424 is 42499353605931.
13950635399424 is a `hidden beast` number, since 1 + 3 + 9 + 5 + 0 + 6 + 3 + 539 + 94 + 2 + 4 = 666.
It can be written as a sum of positive squares in only one way, i.e., 13582467993600 + 368167405824 = 3685440^2 + 606768^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3027479337 + ... + 3027483944.
Almost surely, 213950635399424 is an apocalyptic number.
It is an amenable number.
13950635399424 is an abundant number, since it is smaller than the sum of its proper divisors (26272485682902).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13950635399424 is an equidigital number, since it uses as much as digits as its factorization.
13950635399424 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6054963303 (or 6054963286 counting only the distinct ones).
The product of its (nonzero) digits is 94478400, while the sum is 63.
The spelling of 13950635399424 in words is "thirteen trillion, nine hundred fifty billion, six hundred thirty-five million, three hundred ninety-nine thousand, four hundred twenty-four".
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