Base | Representation |
---|---|
bin | 1100101100011110000001… |
… | …0110100000001011011000 |
3 | 1211102101022212122200022121 |
4 | 3023013200112200023120 |
5 | 3312142203330140211 |
6 | 45404133553431024 |
7 | 2640304021461142 |
oct | 313074026401330 |
9 | 54371285580277 |
10 | 13958112740056 |
11 | 44a1669833291 |
12 | 169521386b474 |
13 | 7a3323bab934 |
14 | 36380d391c92 |
15 | 1931388c3271 |
hex | cb1e05a02d8 |
13958112740056 has 64 divisors (see below), whose sum is σ = 26768282112000. Its totient is φ = 6822242340480.
The previous prime is 13958112740051. The next prime is 13958112740119. The reversal of 13958112740056 is 65004721185931.
It is a super-2 number, since 2×139581127400562 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13958112739985 and 13958112740012.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13958112740051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19471111 + ... + 20175241.
It is an arithmetic number, because the mean of its divisors is an integer number (418254408000).
It is a 1-persistent number, because it is pandigital, but 2⋅13958112740056 = 27916225480112 is not.
Almost surely, 213958112740056 is an apocalyptic number.
It is an amenable number.
13958112740056 is a deficient number, since it is larger than the sum of its proper divisors (12810169371944).
13958112740056 is a wasteful number, since it uses less digits than its factorization.
13958112740056 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 704552 (or 704548 counting only the distinct ones).
The product of its (nonzero) digits is 1814400, while the sum is 52.
The spelling of 13958112740056 in words is "thirteen trillion, nine hundred fifty-eight billion, one hundred twelve million, seven hundred forty thousand, fifty-six".
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