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139873439 is a prime number
BaseRepresentation
bin10000101011001…
…00110010011111
3100202012022021202
420111210302133
5241301422224
621513550115
73315622166
oct1025446237
9322168252
10139873439
1171a55a92
123aa1533b
1322c94864
14148103dd
15c42deae
hex8564c9f

139873439 has 2 divisors, whose sum is σ = 139873440. Its totient is φ = 139873438.

The previous prime is 139873423. The next prime is 139873451. The reversal of 139873439 is 934378931.

It is a happy number.

139873439 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 139873439 - 24 = 139873423 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 139873393 and 139873402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (139873499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69936719 + 69936720.

It is an arithmetic number, because the mean of its divisors is an integer number (69936720).

Almost surely, 2139873439 is an apocalyptic number.

139873439 is a deficient number, since it is larger than the sum of its proper divisors (1).

139873439 is an equidigital number, since it uses as much as digits as its factorization.

139873439 is an evil number, because the sum of its binary digits is even.

The product of its digits is 489888, while the sum is 47.

The square root of 139873439 is about 11826.8101785731. The cubic root of 139873439 is about 519.0928946200.

The spelling of 139873439 in words is "one hundred thirty-nine million, eight hundred seventy-three thousand, four hundred thirty-nine".