1400120014003 has 2 divisors, whose sum is σ = 1400120014004. Its totient is φ = 1400120014002.

The previous prime is 1400120014001. The next prime is 1400120014019. The reversal of 1400120014003 is 3004100210041.

It is an a-pointer prime, because the next prime (1400120014019) can be obtained adding 1400120014003 to its sum of digits (16).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1400120014003 - 2¹ = 1400120014001 is a prime.

It is a super-2 number, since 2×1400120014003² (a number of 25 digits) contains 22 as substring.

Together with 1400120014001, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1400120014001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700060007001 + 700060007002.

It is an arithmetic number, because the mean of its divisors is an integer number (700060007002).

Almost surely, 2^{1400120014003} is an apocalyptic number.

1400120014003 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400120014003 is an equidigital number, since it uses as much as digits as its factorization.

1400120014003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 1400120014003 its reverse (3004100210041), we get a palindrome (4404220224044).

The spelling of 1400120014003 in words is "one trillion, four hundred billion, one hundred twenty million, fourteen thousand, three".