1400402113001 has 2 divisors, whose sum is σ = 1400402113002. Its totient is φ = 1400402113000.

The previous prime is 1400402112983. The next prime is 1400402113003. The reversal of 1400402113001 is 1003112040041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1014542490025 + 385859622976 = 1007245^2 + 621176^2 .

It is a cyclic number.

It is not a de Polignac number, because 1400402113001 - 2³⁴ = 1383222243817 is a prime.

It is a super-2 number, since 2×1400402113001² (a number of 25 digits) contains 22 as substring.

Together with 1400402113003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1400402113003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 700201056500 + 700201056501.

It is an arithmetic number, because the mean of its divisors is an integer number (700201056501).

Almost surely, 2^{1400402113001} is an apocalyptic number.

It is an amenable number.

1400402113001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1400402113001 is an equidigital number, since it uses as much as digits as its factorization.

1400402113001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1400402113001 its reverse (1003112040041), we get a palindrome (2403514153042).

The spelling of 1400402113001 in words is "one trillion, four hundred billion, four hundred two million, one hundred thirteen thousand, one".