1400433431130 has 48 divisors (see below), whose sum is σ = 3766683028680. Its totient is φ = 360571365504.

The previous prime is 1400433431093. The next prime is 1400433431149. The reversal of 1400433431130 is 311343340041.

1400433431130 is a `hidden beast` number, since 14 + 0 + 0 + 4 + 334 + 311 + 3 + 0 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 1028993158449 + 371440272681 = 1014393^2 + 609459^2 .

It is a super-2 number, since 2×1400433431130² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1400433431094 and 1400433431103.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 268279657 + ... + 268284876.

Almost surely, 2^{1400433431130} is an apocalyptic number.

1400433431130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1400433431130 is an abundant number, since it is smaller than the sum of its proper divisors (2366249597550).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1400433431130 is a wasteful number, since it uses less digits than its factorization.

1400433431130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 536564575 (or 536564572 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 1400433431130 its reverse (311343340041), we get a palindrome (1711776771171).

The spelling of 1400433431130 in words is "one trillion, four hundred billion, four hundred thirty-three million, four hundred thirty-one thousand, one hundred thirty".