Base | Representation |
---|---|
bin | 1100101111101010111000… |
… | …1010010011010001010111 |
3 | 1211121122021101202220122021 |
4 | 3023322232022103101113 |
5 | 3314042314421134021 |
6 | 45445310502114011 |
7 | 2644261545236425 |
oct | 313725612232127 |
9 | 54548241686567 |
10 | 14013105255511 |
11 | 4512a1966106a |
12 | 16a3a0071b907 |
13 | 7a85790895cb |
14 | 366348b96115 |
15 | 1947a66e1c41 |
hex | cbeae293457 |
14013105255511 has 2 divisors, whose sum is σ = 14013105255512. Its totient is φ = 14013105255510.
The previous prime is 14013105255509. The next prime is 14013105255521. The reversal of 14013105255511 is 11555250131041.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14013105255511 - 21 = 14013105255509 is a prime.
It is a super-2 number, since 2×140131052555112 (a number of 27 digits) contains 22 as substring.
Together with 14013105255509, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14013105255521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006552627755 + 7006552627756.
It is an arithmetic number, because the mean of its divisors is an integer number (7006552627756).
Almost surely, 214013105255511 is an apocalyptic number.
14013105255511 is a deficient number, since it is larger than the sum of its proper divisors (1).
14013105255511 is an equidigital number, since it uses as much as digits as its factorization.
14013105255511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15000, while the sum is 34.
Adding to 14013105255511 its reverse (11555250131041), we get a palindrome (25568355386552).
The spelling of 14013105255511 in words is "fourteen trillion, thirteen billion, one hundred five million, two hundred fifty-five thousand, five hundred eleven".
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