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14013133117 is a prime number
BaseRepresentation
bin11010000110011111…
…10111000100111101
31100011121011220211021
431003033313010331
5212144330224432
610234302024141
71004154444334
oct150317670475
940147156737
1014013133117
115a41059355
122870b78051
131424259859
1496d134d1b
15570379697
hex3433f713d

14013133117 has 2 divisors, whose sum is σ = 14013133118. Its totient is φ = 14013133116.

The previous prime is 14013133021. The next prime is 14013133139. The reversal of 14013133117 is 71133131041.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12856384996 + 1156748121 = 113386^2 + 34011^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14013133117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14013133091 and 14013133100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14013133177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006566558 + 7006566559.

It is an arithmetic number, because the mean of its divisors is an integer number (7006566559).

Almost surely, 214013133117 is an apocalyptic number.

It is an amenable number.

14013133117 is a deficient number, since it is larger than the sum of its proper divisors (1).

14013133117 is an equidigital number, since it uses as much as digits as its factorization.

14013133117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 14013133117 its reverse (71133131041), we get a palindrome (85146264158).

The spelling of 14013133117 in words is "fourteen billion, thirteen million, one hundred thirty-three thousand, one hundred seventeen".