14013149951 has 2 divisors, whose sum is σ = 14013149952. Its totient is φ = 14013149950.

The previous prime is 14013149903. The next prime is 14013149999. The reversal of 14013149951 is 15994131041.

It is a balanced prime because it is at equal distance from previous prime (14013149903) and next prime (14013149999).

It is a cyclic number.

It is not a de Polignac number, because 14013149951 - 2³⁰ = 12939408127 is a prime.

It is a super-2 number, since 2×14013149951² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14013149551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7006574975 + 7006574976.

It is an arithmetic number, because the mean of its divisors is an integer number (7006574976).

Almost surely, 2^14013149951 is an apocalyptic number.

14013149951 is a deficient number, since it is larger than the sum of its proper divisors (1).

14013149951 is an equidigital number, since it uses as much as digits as its factorization.

14013149951 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 38.

The spelling of 14013149951 in words is "fourteen billion, thirteen million, one hundred forty-nine thousand, nine hundred fifty-one".