140224331327 has 2 divisors, whose sum is σ = 140224331328. Its totient is φ = 140224331326.

The previous prime is 140224331293. The next prime is 140224331329. The reversal of 140224331327 is 723133422041.

140224331327 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140224331327 - 2⁶ = 140224331263 is a prime.

It is a super-3 number, since 3×140224331327³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 140224331329, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 140224331293 and 140224331302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (140224331329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70112165663 + 70112165664.

It is an arithmetic number, because the mean of its divisors is an integer number (70112165664).

Almost surely, 2^140224331327 is an apocalyptic number.

140224331327 is a deficient number, since it is larger than the sum of its proper divisors (1).

140224331327 is an equidigital number, since it uses as much as digits as its factorization.

140224331327 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 32.

Adding to 140224331327 its reverse (723133422041), we get a palindrome (863357753368).

The spelling of 140224331327 in words is "one hundred forty billion, two hundred twenty-four million, three hundred thirty-one thousand, three hundred twenty-seven".