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140343411324 = 22397120569941
BaseRepresentation
bin1000001010110100011…
…1101000001001111100
3111102020202212222112010
42002231013220021330
54244410403130244
6144250050211220
713065561212334
oct2025507501174
9442222788463
10140343411324
1154579219156
1223248883b10
1310307a7c26c
146b150a20c4
1539b5e57eb9
hex20ad1e827c

140343411324 has 24 divisors (see below), whose sum is σ = 330843920848. Its totient is φ = 46298856960.

The previous prime is 140343411317. The next prime is 140343411359. The reversal of 140343411324 is 423114343041.

It is a junction number, because it is equal to n+sod(n) for n = 140343411291 and 140343411300.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60283807 + ... + 60286134.

Almost surely, 2140343411324 is an apocalyptic number.

It is an amenable number.

140343411324 is an abundant number, since it is smaller than the sum of its proper divisors (190500509524).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140343411324 is a wasteful number, since it uses less digits than its factorization.

140343411324 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120570045 (or 120570043 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 140343411324 its reverse (423114343041), we get a palindrome (563457754365).

The spelling of 140343411324 in words is "one hundred forty billion, three hundred forty-three million, four hundred eleven thousand, three hundred twenty-four".

Divisors: 1 2 3 4 6 12 97 194 291 388 582 1164 120569941 241139882 361709823 482279764 723419646 1446839292 11695284277 23390568554 35085852831 46781137108 70171705662 140343411324