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14040101141413 is a prime number
BaseRepresentation
bin1100110001001111011100…
…1111011011101110100101
31211201012221210022000012021
43030103313033123232211
53320013111343011123
645505533341423141
72646235536416224
oct314236717335645
954635853260167
1014040101141413
114523412084776
1216a909556aab1
137aac8bc596a9
1436778a246cbb
15195336712c5d
hexcc4f73dbba5

14040101141413 has 2 divisors, whose sum is σ = 14040101141414. Its totient is φ = 14040101141412.

The previous prime is 14040101141387. The next prime is 14040101141467. The reversal of 14040101141413 is 31414110104041.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13549930326529 + 490170814884 = 3681023^2 + 700122^2 .

It is a cyclic number.

It is not a de Polignac number, because 14040101141413 - 233 = 14031511206821 is a prime.

It is a super-2 number, since 2×140401011414132 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14040101142413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7020050570706 + 7020050570707.

It is an arithmetic number, because the mean of its divisors is an integer number (7020050570707).

Almost surely, 214040101141413 is an apocalyptic number.

It is an amenable number.

14040101141413 is a deficient number, since it is larger than the sum of its proper divisors (1).

14040101141413 is an equidigital number, since it uses as much as digits as its factorization.

14040101141413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 14040101141413 its reverse (31414110104041), we get a palindrome (45454211245454).

The spelling of 14040101141413 in words is "fourteen trillion, forty billion, one hundred one million, one hundred forty-one thousand, four hundred thirteen".