Search a number
-
+
14042351471 is a prime number
BaseRepresentation
bin11010001001111110…
…10100011101101111
31100020122011100212112
431010333110131233
5212224320221341
610241224154235
71004661006131
oct150477243557
940218140775
1014042351471
115a565a5555
12287a90897b
13142a319b15
14972d7d051
15572bebaeb
hex344fd476f

14042351471 has 2 divisors, whose sum is σ = 14042351472. Its totient is φ = 14042351470.

The previous prime is 14042351447. The next prime is 14042351473. The reversal of 14042351471 is 17415324041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14042351471 - 210 = 14042350447 is a prime.

It is a super-3 number, since 3×140423514713 (a number of 31 digits) contains 333 as substring.

Together with 14042351473, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14042351473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7021175735 + 7021175736.

It is an arithmetic number, because the mean of its divisors is an integer number (7021175736).

Almost surely, 214042351471 is an apocalyptic number.

14042351471 is a deficient number, since it is larger than the sum of its proper divisors (1).

14042351471 is an equidigital number, since it uses as much as digits as its factorization.

14042351471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 32.

The spelling of 14042351471 in words is "fourteen billion, forty-two million, three hundred fifty-one thousand, four hundred seventy-one".