Base | Representation |
---|---|
bin | 1100110001011110100011… |
… | …0000001000101101001110 |
3 | 1211201121102011121221020011 |
4 | 3030113220300020231032 |
5 | 3320044411133221220 |
6 | 45511443403343434 |
7 | 2646441130016044 |
oct | 314275060105516 |
9 | 54647364557204 |
10 | 14044153023310 |
11 | 45251012845a3 |
12 | 16a9a26521b7a |
13 | 7ab486544c47 |
14 | 367a52424394 |
15 | 1954c22d565a |
hex | cc5e8c08b4e |
14044153023310 has 32 divisors (see below), whose sum is σ = 26839436780160. Its totient is φ = 5272803958272.
The previous prime is 14044153023233. The next prime is 14044153023323. The reversal of 14044153023310 is 1332035144041.
It is a super-3 number, since 3×140441530233103 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 112488925 + ... + 112613704.
It is an arithmetic number, because the mean of its divisors is an integer number (838732399380).
Almost surely, 214044153023310 is an apocalyptic number.
14044153023310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14044153023310 is a deficient number, since it is larger than the sum of its proper divisors (12795283756850).
14044153023310 is a wasteful number, since it uses less digits than its factorization.
14044153023310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 225103020.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 14044153023310 its reverse (1332035144041), we get a palindrome (15376188167351).
The spelling of 14044153023310 in words is "fourteen trillion, forty-four billion, one hundred fifty-three million, twenty-three thousand, three hundred ten".
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