140642116343550 has 36 divisors (see below), whose sum is σ = 377858485910880. Its totient is φ = 37504564358160.

The previous prime is 140642116343549. The next prime is 140642116343581. The reversal of 140642116343550 is 55343611246041.

140642116343550 is a `hidden beast` number, since 1 + 4 + 0 + 6 + 4 + 2 + 1 + 1 + 634 + 3 + 5 + 5 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a junction number, because it is equal to n+sod(n) for n = 140642116343496 and 140642116343505.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 156269017710 + ... + 156269018609.

It is an arithmetic number, because the mean of its divisors is an integer number (10496069053080).

Almost surely, 2^{140642116343550} is an apocalyptic number.

140642116343550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

140642116343550 is an abundant number, since it is smaller than the sum of its proper divisors (237216369567330).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

140642116343550 is a wasteful number, since it uses less digits than its factorization.

140642116343550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312538036337 (or 312538036329 counting only the distinct ones).

The product of its (nonzero) digits is 1036800, while the sum is 45.

Adding to 140642116343550 its reverse (55343611246041), we get a palindrome (195985727589591).

The spelling of 140642116343550 in words is "one hundred forty trillion, six hundred forty-two billion, one hundred sixteen million, three hundred forty-three thousand, five hundred fifty".