Base | Representation |
---|---|
bin | 1100110010110100111011… |
… | …1011101011101101100111 |
3 | 1211210211021021002021101222 |
4 | 3030231032323223231213 |
5 | 3320434404043202131 |
6 | 45530240415210555 |
7 | 2651221565320511 |
oct | 314551673535547 |
9 | 54724237067358 |
10 | 14067342162791 |
11 | 4533a20a09285 |
12 | 16b2418516a5b |
13 | 7b0710857c58 |
14 | 368c120a8bb1 |
15 | 195dcd00687b |
hex | ccb4eeebb67 |
14067342162791 has 2 divisors, whose sum is σ = 14067342162792. Its totient is φ = 14067342162790.
The previous prime is 14067342162733. The next prime is 14067342162793. The reversal of 14067342162791 is 19726124376041.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14067342162791 - 238 = 13792464255847 is a prime.
Together with 14067342162793, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14067342162793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7033671081395 + 7033671081396.
It is an arithmetic number, because the mean of its divisors is an integer number (7033671081396).
Almost surely, 214067342162791 is an apocalyptic number.
14067342162791 is a deficient number, since it is larger than the sum of its proper divisors (1).
14067342162791 is an equidigital number, since it uses as much as digits as its factorization.
14067342162791 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3048192, while the sum is 53.
The spelling of 14067342162791 in words is "fourteen trillion, sixty-seven billion, three hundred forty-two million, one hundred sixty-two thousand, seven hundred ninety-one".
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