14100162431130 has 64 divisors (see below), whose sum is σ = 37988066551680. Its totient is φ = 3721279974912.

The previous prime is 14100162431123. The next prime is 14100162431137. The reversal of 14100162431130 is 3113426100141.

14100162431130 is a `hidden beast` number, since 1 + 4 + 1 + 0 + 0 + 1 + 624 + 3 + 1 + 1 + 30 = 666.

It is an interprime number because it is at equal distance from previous prime (14100162431123) and next prime (14100162431137).

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 14100162431094 and 14100162431103.

It is not an unprimeable number, because it can be changed into a prime (14100162431137) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 269163624 + ... + 269216003.

It is an arithmetic number, because the mean of its divisors is an integer number (593563539870).

Almost surely, 2^{14100162431130} is an apocalyptic number.

14100162431130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14100162431130 is an abundant number, since it is smaller than the sum of its proper divisors (23887904120550).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14100162431130 is a wasteful number, since it uses less digits than its factorization.

14100162431130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 538379740 (or 538379734 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 14100162431130 its reverse (3113426100141), we get a palindrome (17213588531271).

The spelling of 14100162431130 in words is "fourteen trillion, one hundred billion, one hundred sixty-two million, four hundred thirty-one thousand, one hundred thirty".