14104341300 has 108 divisors (see below), whose sum is σ = 47471232480. Its totient is φ = 3223846080.

The previous prime is 14104341289. The next prime is 14104341301. The reversal of 14104341300 is 314340141.

14104341300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14104341301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 465040 + ... + 494439.

Almost surely, 2^14104341300 is an apocalyptic number.

14104341300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14104341300 is an abundant number, since it is smaller than the sum of its proper divisors (33366891180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14104341300 is a wasteful number, since it uses less digits than its factorization.

14104341300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 959510 (or 959496 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 14104341300 its reverse (314340141), we get a palindrome (14418681441).

The spelling of 14104341300 in words is "fourteen billion, one hundred four million, three hundred forty-one thousand, three hundred".