14110420013 has 2 divisors, whose sum is σ = 14110420014. Its totient is φ = 14110420012.

The previous prime is 14110419991. The next prime is 14110420039. The reversal of 14110420013 is 31002401141.

It is a happy number.

14110420013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14110351369 + 68644 = 118787^2 + 262^2 .

It is a cyclic number.

It is not a de Polignac number, because 14110420013 - 2³⁰ = 13036678189 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14110419973 and 14110420000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14110420043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055210006 + 7055210007.

It is an arithmetic number, because the mean of its divisors is an integer number (7055210007).

Almost surely, 2^14110420013 is an apocalyptic number.

It is an amenable number.

14110420013 is a deficient number, since it is larger than the sum of its proper divisors (1).

14110420013 is an equidigital number, since it uses as much as digits as its factorization.

14110420013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 14110420013 its reverse (31002401141), we get a palindrome (45112821154).

The spelling of 14110420013 in words is "fourteen billion, one hundred ten million, four hundred twenty thousand, thirteen".