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14111042021233 is a prime number
BaseRepresentation
bin1100110101010111101110…
…1001011010011101110001
31211222000001210002002112121
43031111323221122131301
53322143403224134413
650002305002554241
72654326530065563
oct315257351323561
954860053062477
1014111042021233
11455050638a773
1216ba993508981
137b48862b1861
1436ad99bbb333
151970d9727b8d
hexcd57ba5a771

14111042021233 has 2 divisors, whose sum is σ = 14111042021234. Its totient is φ = 14111042021232.

The previous prime is 14111042021221. The next prime is 14111042021257. The reversal of 14111042021233 is 33212024011141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7269532186849 + 6841509834384 = 2696207^2 + 2615628^2 .

It is a cyclic number.

It is not a de Polignac number, because 14111042021233 - 217 = 14111041890161 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14111042021198 and 14111042021207.

It is not a weakly prime, because it can be changed into another prime (14111042021533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055521010616 + 7055521010617.

It is an arithmetic number, because the mean of its divisors is an integer number (7055521010617).

Almost surely, 214111042021233 is an apocalyptic number.

It is an amenable number.

14111042021233 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111042021233 is an equidigital number, since it uses as much as digits as its factorization.

14111042021233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 14111042021233 its reverse (33212024011141), we get a palindrome (47323066032374).

The spelling of 14111042021233 in words is "fourteen trillion, one hundred eleven billion, forty-two million, twenty-one thousand, two hundred thirty-three".