Base | Representation |
---|---|

bin | 110101110101… |

… | …001001001111 |

3 | 222112221002011 |

4 | 311311021033 |

5 | 12103030221 |

6 | 1222242051 |

7 | 230641564 |

oct | 65651117 |

9 | 28487064 |

10 | 14111311 |

11 | 7a69045 |

12 | 4886327 |

13 | 2c00cb6 |

14 | 1c3486b |

15 | 138b1e1 |

hex | d7524f |

14111311 has 2 divisors, whose sum is σ = 14111312. Its totient is φ = 14111310.

The previous prime is 14111299. The next prime is 14111323. The reversal of 14111311 is 11311141.

It is a happy number.

It is a m-pointer prime, because the next prime (14111323) can be obtained adding 14111311 to its product of digits (12).

It is a balanced prime because it is at equal distance from previous prime (14111299) and next prime (14111323).

It is a cyclic number.

It is not a de Polignac number, because 14111311 - 2^{7} = 14111183 is a prime.

It is a junction number, because it is equal to *n*+sod(*n*) for *n* = 14111291 and 14111300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14111341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7055655 + 7055656.

It is an arithmetic number, because the mean of its divisors is an integer number (7055656).

Almost surely, 2^{14111311} is an apocalyptic number.

14111311 is a deficient number, since it is larger than the sum of its proper divisors (1).

14111311 is an equidigital number, since it uses as much as digits as its factorization.

14111311 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12, while the sum is 13.

The square root of 14111311 is about 3756.5024956733. The cubic root of 14111311 is about 241.6512918214.

Adding to 14111311 its reverse (11311141), we get a palindrome (25422452).

The spelling of 14111311 in words is "fourteen million, one hundred eleven thousand, three hundred eleven".

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